(4x^2)-13x=0

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Solution for (4x^2)-13x=0 equation: 



(4x^2)-13x=0

a = 4; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·4·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*4}=\frac{0}{8}
=0
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*4}=\frac{26}{8}
=3+1/4
$

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